[docs] add sports scheduling tutorial

docs/make_utilities.jl

@@ -571,6 +571,7 @@ function documentation_structure()
                 "tutorials/linear/multi_objective_project_planning.md",
                 "tutorials/linear/sudoku.md",
                 "tutorials/linear/n-queens.md",
+                "tutorials/linear/sports_scheduling.md",
                 "tutorials/linear/constraint_programming.md",
                 "tutorials/linear/callbacks.md",
                 "tutorials/linear/lp_sensitivity.md",

docs/src/tutorials/linear/sports_scheduling.jl

@@ -0,0 +1,174 @@
+# Copyright (c) 2026 Oscar Dowson and contributors                               #src
+#                                                                                #src
+# Permission is hereby granted, free of charge, to any person obtaining a copy   #src
+# of this software and associated documentation files (the "Software"), to deal  #src
+# in the Software without restriction, including without limitation the rights   #src
+# to use, copy, modify, merge, publish, distribute, sublicense, and/or sell      #src
+# copies of the Software, and to permit persons to whom the Software is          #src
+# furnished to do so, subject to the following conditions:                       #src
+#                                                                                #src
+# The above copyright notice and this permission notice shall be included in all #src
+# copies or substantial portions of the Software.                                #src
+#                                                                                #src
+# THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR     #src
+# IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,       #src
+# FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE    #src
+# AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER         #src
+# LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,  #src
+# OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE  #src
+# SOFTWARE.                                                                      #src
+
+# # Sport scheduling
+
+# **This tutorial was adapted from an [example written by Eli Towle](https://publicsectororcourse.wordpress.com/2016/05/09/optimization-in-julia/)
+# in 2016 as part of an operations research course at the University of
+# Wisconsin-Madison.**
+
+# The purpose of this tutorial is to demonstrate a simple model for scheduling
+# round-robin tournaments. As teams, it uses the [Big 10](https://en.wikipedia.org/wiki/Big_Ten_Conference).
+# (You might notice that there are more than 10 teams. Our example was also
+# written before the expansion of the Conference in 2024.)
+
+# ## Required packages
+
+# This tutorial uses the following packages:
+
+using JuMP
+import HiGHS
+
+# ## Basic model
+
+# Here are the teams in our tournament:
+
+M = [
+    #!format:off
+    "Ind", "UMD", "UMich", "MSU", "OSU", "Penn", "Rtgrs", "Ill", "Iowa", "UMN",
+    "UNL", "NU", "Purd", "UW",
+    #!format: on
+];
+
+# For each team to play each other exactly once, we need the number of teams - 1
+# weeks:
+
+T = length(M) - 1;
+
+# Now we create a JuMP model to build our optimzation problem:
+
+model = Model(HiGHS.Optimizer);
+
+# Variable: a binary which is true for `x[m,n,t]` if team `m` is playing `n` at
+# home in week `t`.
+
+@variable(model, x[M, M, 1:T], Bin);
+
+# Constraint: each team `m` can never play themselves.
+
+@constraint(model, [m in M, t in 1:T], x[m, m, t] == 0);
+
+# Constraint: each team `m` can play at most once per day
+
+@constraint(model, [m in M, t in 1:T], sum(x[m, :, t]) + sum(x[:, m, t]) <= 1);
+
+# Constraint: every team `m` plays at least half home games
+
+@constraint(model, [m in M], div(T, 2) <= sum(x[m, :, :]) <= div(T, 2) + 1);
+
+# Constraint: no more than two away games in any three-game window
+
+@constraint(model, [m in M, t in 1:(T-2)], sum(x[:, m, t:(t+2)]) <= 2);
+
+# Constraint: every team must play every other team exactly once
+
+@constraint(
+    model,
+    [m in M, n in M; m != n],
+    sum(x[m, n, :]) + sum(x[n, m, :]) == 1,
+);
+
+# Now we can solve our model:
+
+set_silent(model)
+optimize!(model)
+assert_is_solved_and_feasible(model)
+
+# and print the schedule:
+
+function print_schedule(M::Vector{String}, T::Int, Y::AbstractArray{Bool})
+    println("Week ", join(rpad.(M, 6), ' '))
+    for t in 1:T
+        print(rpad(t, 5))
+        for m in M, n in M
+            if Y[m, n, t]
+                print(rpad(n, 7))
+            elseif Y[n, m, t]
+                print("@", rpad(n, 6))
+            end
+        end
+        println()
+    end
+    return
+end
+
+Y = round.(Bool, value.(x))
+print_schedule(M, T, Y)
+
+# This schedule is okay, but it features a large number of back-to-back away
+# games. Let's count them:
+
+number_of_back_to_back_away_games =
+    sum(round(Int, value(sum(x[:, m, (t-1):t]))) == 2 for m in M, t in 2:T)
+
+# A better schedule would minimize this quantity.
+
+# ## Minimizing the number of back-to-back away games
+
+# To minimize the number of back-to-back away games, we modify our model.
+
+# Variable: a binary which is true for `y[m,t]` if team `m` is playing
+# back-to-back away games in week `t`.
+
+@variable(model, y[M, 2:T], Bin);
+
+# Objective: minimize the number of back-to-back away games
+
+@objective(model, Min, sum(y));
+
+# Constraint: count back-to-back away games
+
+@constraint(model, [m in M, t in 2:T], y[m, t] >= sum(x[:, m, (t-1):t]) - 1);
+
+# Now we can solve our model. However, this problem is actually very difficult
+# to solve to optimality. Rather than wait a very long time, we set a time limit
+# so that this documentation doesn't take too long to build:
+
+set_time_limit_sec(model, 30.0)
+
+# We're also going to set a start value based on the previous solution:
+
+set_start_value.(x, Y)
+for m in M, t in 2:T
+    set_start_value(y[m, t], sum(Y[:, m, (t-1):t]) - 1)
+end
+
+# Now we can optimize:
+
+optimize!(model)
+
+# Because we hit a time limit, we can't use [`assert_is_solved_and_feasible`](@ref),
+# but we still check that we found a feasible primal solution:
+
+@assert termination_status(model) == TIME_LIMIT
+@assert primal_status(model) == FEASIBLE_POINT
+
+# This solution has fewer back-to-back away games:
+
+number_of_back_to_back_away_games =
+    sum(round(Int, value(sum(x[:, m, (t-1):t]))) == 2 for m in M, t in 2:T)
+
+# And the final schedule is:
+
+Y = round.(Bool, value.(x))
+print_schedule(M, T, Y)
+
+# Try running the model for longer. What is the smallest number of back-to-back
+# away games you can find?

docs/styles/config/vocabularies/JuMP/accept.txt

@@ -300,6 +300,7 @@ Tanneau
 Teghem
 Tejada
 Tillmann
+Towle
 Ulungu
 Vanaret
 Vandenberghe