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56 changes: 56 additions & 0 deletions NQueens.java
Original file line number Diff line number Diff line change
@@ -0,0 +1,56 @@
import java.util.*;

// Row wise 0 to n
// O(n * n!) time, O(n) space
class Solution {
public List<List<String>> solveNQueens(int n) {
List<List<String>> ans = new ArrayList<>();
char[][] board = new char[n][n];

for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
board[i][j] = '.';
}
}
helper(0, n, board, ans);
return ans;
}

private void helper(int row, int n, char[][] board, List<List<String>> ans) {
if (row == n) {
List<String> path = new ArrayList<>();
for (int i = 0; i < n; i++) {
path.add(new String(board[i])); // new string for each board
}
ans.add(new ArrayList<>(path));
return;
}

for (int col = 0; col < n; col++) {
if (isValid(row, col, n, board)) {
board[row][col] = 'Q';
helper(n, row+1, board, ans);
board[row][col] = '.'; //backtrack
}
}
}

private boolean isValid(int row, int col, int n, char[][] board) {
// check vertical
for (int i = 0; i < row; i++) {
if (board[i][col] == 'Q') return false;
}

// check left upper
for (int i = row, j = col; i >= 0 && j >= 0; i--, j--) {
if (board[i][j] == 'Q') return false;
}

// check right upper
for (int i = row, j = col; i >= 0 && j < n; i--, j++) {
if (board[i][j] == 'Q') return false;
}

return true;
}
}
48 changes: 48 additions & 0 deletions WordSearch.java
Original file line number Diff line number Diff line change
@@ -0,0 +1,48 @@
// O(n * m * 3^L) time, O(L) space
class Solution {
public boolean exist(char[][] board, String word) {
int n = board.length;
int m = board[0].length;

int[][] dirs = new int[][] {
{0,1},{0,-1},{1,0},{-1,0}
};

boolean[][] visited = new boolean[n][m];

for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
if (board[i][j] == word.charAt(0)) {
if (dfs(board, i, j, n, m, word, 0, dirs, visited)) {
return true;
}
}
}
}
return false;
}

private boolean dfs(char[][] board, int i, int j, int n, int m, String word, int wordIdx, int[][] dirs, boolean[][] visited) {
if (board[i][j] != word.charAt(wordIdx)) return false;

if (wordIdx == word.length() - 1) return true;

visited[i][j] = true; // mark as visited

for (int[] dir : dirs) {
int r = i + dir[0];
int c = j + dir[1];

if (r >= 0 && c >= 0 && r < n && c < m && !visited[r][c]) {
if (dfs(board, r, c, n, m, word, wordIdx+1, dirs, visited)) {
visited[r][c] = false;
return true;
}
}
}

visited[i][j] = false; // backtrack

return false;
}
}